Python Set symmetric_difference_update()

A = {'a', 'c', 'd'}
B = {'c', 'd', 'e' }

# updates A with the symmetric difference of A and B
A.symmetric_difference_update(B)

print(A)

# Output: {a, e}

symmetric_difference_update() Syntax

The syntax of the symmetric_difference_update() method is:

A.symmetric_difference_update(B)

Here, A and B are two sets.

symmetric_difference_update() Parameter

The symmetric_difference_update() method takes a single parameter:

• B - a set that pairs with set A to find non-similar items of both sets

symmetric_difference_update() Return Value

The symmetric_difference_update() method doesn't return any value.

Example: Python Set symmetric_difference_update()

# create two sets A and B
A = {'Python', 'Java', 'Go'}
B = {'Python', 'JavaScript', 'C' }

print('Original Set A:', A)

# updates A with the symmetric difference of A and B
A.symmetric_difference_update(B)

print('Updated Set A:', A)

Output

Original Set A: {'Python', 'Java', 'Go'}
Updated Set A: {'Java', 'C', 'Go', 'JavaScript'}

In the above example, we have used the symmetric_difference_update() method that returns the set with items that are unique in both sets i.e. it removes similar items (intersection) of the set.

Here, set A is calling the method, so the result is updated to set A. Whereas, the set B remains unchanged.

Also Read:

• Python Set symmetric difference()