C Program to Convert Binary Number to Decimal and vice-versa

Example 1: C Program to Convert Binary Number to Decimal

#include <stdio.h>

// function prototype
long long convert(long long);

int main() {

    long long n;

    printf("Enter a binary number: ");
    scanf("%lld", &n);

    printf("%lld in binary = %lld in decimal", n, convert(n));

    return 0;
}

// function definition
long long convert(long long n) {

    long long dec = 0;
    int i = 0, rem;

    while (n != 0) {

        // get remainder of n divided by 10
        rem = n % 10;

        // add the rem * (2 ^ i) to dec
        dec += rem << i; // Using bitwise shift instead of pow

        // divide n by 10
        n /= 10;

        // increment i
        ++i;
    }

    return dec;
}

Output

Enter a binary number: 1101
1101 in binary = 13 in decimal

In the program, we have included the header file math.h to perform mathematical operations in the program.

We ask the user to enter a binary number and pass it to the convert() function to convert it decimal.

Suppose n = 1101. Let's see how the while loop in the convert() function works.

So, 1101 in binary is 13 in decimal.

Now, let's see how we can change the decimal number into a binary number.

Example 2: C Program to convert decimal number to binary

// convert decimal to binary

#include <stdio.h>
#include <math.h>

// function prototype
long long convert(int);

int main() {
    
  int n;
  long long bin;
  
  printf("Enter a decimal number: ");
  scanf("%d", &n);
  
  // convert to binary using the convert() function
  bin = convert(n);
  
  printf("%d in decimal =  %lld in binary", n, bin);

  return 0;
}

// function to convert decimal to binary
long long convert(int n) {

  // variable to store the result
  long long bin = 0;

  int rem, i = 1;

  // loop to convert to binary
  while (n != 0) {
    
    // get remainder of n divided by 2
    rem = n % 2;
    
    // divide n by 2
    n /= 2;
    
    // multiply remainder by i
    // add the product to bin
    bin += rem * i;
    
    // multiply i by 10
    i *= 10;
  }

  return bin;
}

Output

Enter a decimal number: 13
13 in decimal = 1101 in binary

Suppose n = 13. Let's see how the while loop in the convert() function works.

Thus, 13 in decimal is 1101 in binary.