Python Program to Count the Number of Digits Present In a Number

Example 1: Count Number of Digits in an Integer using while loop

num = 3452
count = 0

while num != 0:
    num //= 10
    count += 1

print("Number of digits: " + str(count))

Output

Number of digits: 4

In this program, the while loop is iterated until the test expression num != 0 is evaluated to 0 (false).

1. After the first iteration, num will be divided by 10 and its value will be 345. Then, the count is incremented to 1.
2. After the second iteration, the value of num will be 34 and the count is incremented to 2.
3. After the third iteration, the value of num will be 3 and the count is incremented to 3.
4. After the fourth iteration, the value of num will be 0 and the count is incremented to 4.
5. Then the test expression is evaluated to false and the loop terminates.

Example 2: Using inbuilt methods

num = 123456
print(len(str(num)))

Output

6

In the above example, we first convert the integer value into string by using str(). Then, we find the length of the string using len().

Also Read:

• Python Program to Count the Number of Occurrence of a Character in String